45x^2+88x-48=0

Solution for 45x^2+88x-48=0 equation:

45x^2+88x-48=0

a = 45; b = 88; c = -48;
Δ = b2-4ac
Δ = 882-4·45·(-48)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-128}{2*45}=\frac{-216}{90}
=-2+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+128}{2*45}=\frac{40}{90}
=4/9
$